Summit - An Interactive Algebra Journey/Summit, An Interactive Algebra Journey.iso/SUMMIT/UTILS/C2/S5/P2

Text File | 1995-11-01 | 3.3 KB | 42 lines

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2,5(2,19)1,3(1,20)4(1,30)n(1=2)n(4=5)n(4<10&5<10)
4(1e3*)5(2e3*)10(2e4*)11(1e5*)n(4l10l/z<>5l10l/z)
Use the cross products to decide whetherthis proportion is true or false.512 = 45iT14Use the cross products to decide whetherthis proportion is true or false.512 = 452:2 ÿ 4:2 = 101:2 ÿ 5:2 = 11pSince the cross products are c2EQUALc0,the proportion is c2TRUEc0.
true
2(2,19)1(1,20)3(2,10)n(1=2)
4(1e3*)5(2e3*)10(2e4*)11(1e5*)n(4l10l/z<>5l10l/z)
Use the cross products to decide whetherthis proportion is true or false.512 = 45iT14Use the cross products to decide whetherthis proportion is true or false.512 = 452:2 ÿ 4:2 = 101:2 ÿ 5:2 = 11pSince the cross products are c2EQUALc0, theproportion is c2TRUEc0.
true
2(2,19)1(1,20)3(2,10)n(1=2)
4(1e3*)5(2e3*)10(2e4*)11(1e5*)n(4l10l/z<>5l10l/z)
Use the cross products to decide whetherthis proportion is true or false.512 = 45iT14Use the cross products to decide whetherthis proportion is true or false.512 = 452:2 ÿ 4:2 = 101:2 ÿ 5:2 = 11pSince the cross products are c2EQUALc0, theproportion is c2TRUEc0.
true
2,5(2,19)1(1,20)4(1,30)n(1=2)n(4=5)n(4<10&5<10)
10(2e4*)11(1e5*)n(10=11)
Use the cross products to decide whetherthis proportion is true or false.512 = 45iT14Use the cross products to decide whetherthis proportion is true or false.512 = 452:2 ÿ 4:2 = 101:2 ÿ 5:2 = 11pSince the cross products are c2NOT EQUALc0,the proportion is c2FALSEc0.
false
1,2(2,5)3(2,9)20(1,2)
21(2e1*20+)22(2e1*1+)23(21e3*)24(22e3*)7(2e3*)48(4e21l10l/z-)
Use the cross products to decide whetherthis proportion is true or false.5 112 3 = 217iT14Use the cross products to decide whetherthis proportion is true or false.5 112 3 = 217+483 ÿ 21 = 2320Convert to an improper20fraction.  112 ÿ 7:2 = 222 ÿ 7p8  = 24pSince the cross products are #if(22<>21)c2NOTc0 #endifc2EQUALc0,the proportion is #if(22=21)c2TRUEc0.#elsec2FALSEc0.#endif
#if(21=22)true#elsefalse#endif
1,2(2,5)3(2,9)20(1,2)
21(2e1*20+)22(2e1*1+)23(21e3*)24(22e3*)7(2e3*)48(4e21l10l/z-)
Use the cross products to decide whetherthis proportion is true or false.5 112 3 = 217iT14Use the cross products to decide whetherthis proportion is true or false.5 112 3 = 217+483 ÿ 21 = 2320Convert to an improper20fraction.  112 ÿ 7:2 = 222 ÿ 7p8  = 24pSince the cross products are #if(22<>21)c2NOTc0 #endifc2EQUALc0,the proportion is #if(22=21)c2TRUEc0.#elsec2FALSEc0.#endif
#if(21=22)true#elsefalse#endif
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